算一任意长度字符串中不同的字符以及它的个数代码,Asp.NET代码库,德仔网

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【Asp.NET】算一任意长度字符串中不同的字符以及它的个数

作者: / 发布于2016/4/26/ 629

static void Main(string[] args)  
{  
  
    string a = "abcdefgabc";  
    int i = a.Length;  
    while (i > 0)  
    {  
        Console.WriteLine(a[0].ToString() + ":");  
        a = a.Replace(a[0].ToString(), "");  
        Console.Write(i - a.Length);  
        Console.WriteLine();  
        i = a.Length;  
    }  
  
  
}  



static void Main(string[] args)  
   {  
       Console.WriteLine("请输入字符串：");  
       string str = Console.ReadLine();  
       CharCount(str);  
   }  
  
   public static void CharCount(string str)  
   {  
       if (str == string.Empty) return;  
       char ch = str.Substring(0).ToCharArray()[0];  
       int num = str.Split(ch).Length - 1;  
       Console.WriteLine("char: {0}   num: {1}", ch, num);  
       CharCount(str.Replace(ch.ToString(), ""));  
   }  



static void Main(string[] args)  
       {  
           string s = "abcdefgabc";  
           Dictionary<char, int> list = new Dictionary<char, int>();  
           for (int i = 0; i < s.Length; i++)  
           {  
               if (list.ContainsKey(s[i]))  
               {  
                   list[s[i]]++;  
               }  
               else  
               {  
                   list.Add(s[i], 1);  
               }  
           }  
  
           foreach (char key in list.Keys)  
           {  
               Console.WriteLine("{0}:{1}", key, list[key]);  
           }  
       }  


static void Main()  
     {  
         calculateChar("wshuguo");  
     }  
     //求算一任意长度字符串中不同的字符以及它的个数  
     public static void calculateChar(string anyStr)  
     {  
         var query = from letter in anyStr  
                     group letter by letter into g  
                     select new  
                     {  
                         letter = g.Key,  
                         count = g.Count()  
                     };  
         query.ToList().ForEach(q => Console.WriteLine("letter:{0},count:{1}", q.letter, q.count));  
     }

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