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【Python】 python获取当前日期前后N天或N月的日期

作者: / 发布于2011/1/4/ 608

<div>!/usr/bin/python
'''
Filename: "utildate.py"
author: "zhangsong"
date : "2009-03-24"
version: "1.00"
'''
from time import strftime, localtime
from datetime import timedelta, date
import calendar

year = strftime("%Y",localtime())
mon = strftime("%m",localtime())
day = strftime("%d",localtime())
hour = strftime("%H",localtime())
min = strftime("%M",localtime())
sec = strftime("%S",localtime())


def today():
 '''
 get today,date format="YYYY-MM-DD"
 '''
 return date.today()

def todaystr():
 '''
 get date string
 date format="YYYYMMDD"
 '''
 return year+mon+day

def datetime():
 '''
 get datetime,format="YYYY-MM-DD HH:MM:SS"
 '''
 return strftime("%Y-%m-%d %H:%M:%S",localtime())

def datetimestr():
 '''
 get datetime string
 date format="YYYYMMDDHHMMSS"
 '''
 return year+mon+day+hour+min+sec

def getdayofday(n=0):
 '''
 if n>=0,date is larger than today
 if n<0,date is less than today
 date format = "YYYY-MM-DD"
 '''
 if(n<0):
 n = abs(n)
 return date.today()-timedelta(days=n)
 else:
 return date.today()+timedelta(days=n)

def getdaysofmonth(year,mon):
 '''
 get days of month
 '''
 return calendar.monthrange(year, mon)[1]

def getfirstdayofmonth(year,mon):
 '''
 get the first day of month
 date format = "YYYY-MM-DD"
 '''
 days="01"
 if(int(mon)<10):
 mon = "0"+str(int(mon))
 arr = (year,mon,days)
 return "-".join("%s" %i for i in arr)

def getlastdayofmonth(year,mon):
 '''
 get the last day of month
 date format = "YYYY-MM-DD"
 '''
 days=calendar.monthrange(year, mon)[1]
 mon = addzero(mon)
 arr = (year,mon,days)
 return "-".join("%s" %i for i in arr)

def get_firstday_month(n=0):
 '''
 get the first day of month from today
 n is how many months
 '''
 (y,m,d) = getyearandmonth(n)
 d = "01"
 arr = (y,m,d)
 return "-".join("%s" %i for i in arr)

def get_lastday_month(n=0):
 '''
 get the last day of month from today
 n is how many months
 '''
 return "-".join("%s" %i for i in getyearandmonth(n))
 
def get_today_month(n=0):
 '''
 get last or next month's today
 n is how many months
 date format = "YYYY-MM-DD"
 '''
 (y,m,d) = getyearandmonth(n)
 arr=(y,m,d)
 if(int(day)<int(d)):
 arr = (y,m,day)
 return "-".join("%s" %i for i in arr)

def getyearandmonth(n=0):
 '''
 get the year,month,days from today
 befor or after n months
 '''
 thisyear = int(year)
 thismon = int(mon)
 totalmon = thismon+n
 if(n>=0):
 if(totalmon<=12):
 days = str(getdaysofmonth(thisyear,totalmon))
 totalmon = addzero(totalmon)
 return (year,totalmon,days)
 else:
 i = totalmon/12
 j = totalmon%12
 if(j==0):
 i-=1
 j=12
 thisyear += i
 days = str(getdaysofmonth(thisyear,j))
 j = addzero(j)
 return (str(thisyear),str(j),days)
 else:
 if((totalmon>0) and (totalmon<12)):
 days = str(getdaysofmonth(thisyear,totalmon))
 totalmon = addzero(totalmon)
 return (year,totalmon,days)
 else:
 i = totalmon/12
 j = totalmon%12
 if(j==0):
 i-=1
 j=12
 thisyear +=i
 days = str(getdaysofmonth(thisyear,j))
 j = addzero(j)
 return (str(thisyear),str(j),days)

def addzero(n):
 '''
 add 0 before 0-9
 return 01-09
 '''
 nabs = abs(int(n))
 if(nabs<10):
 return "0"+str(nabs)
 else:
 return nabs

#print today()
#print addzero(10)
print get_today_month(-1)
print get_lastday_month(3)
print get_firstday_month(3) 
</div>

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