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【Python】 Python CET查分

作者:Sephiroth / 发布于2011/1/10/ 610

<div>!/usr/bin/python
# -*- coding: utf-8 -*-
import sys, urllib2
def CetQuery(band, exam_id):
 """CETQuery version 0.2 2009.2.28
 An Exercise Program by PT, GZ University
 Author Blog: <a href="http://apt-blog.co.cc">http://apt-blog.co.cc</a> , Welcome to Drop by.
 """
 #查询连接
 cet = "<a href="http://cet.99sushe.com/cetscore_99sushe0902.html?t">http://cet.99sushe.com/cetscore_99sushe0902.html?t</a>=" + band + "&id=" + exam_id
 print "Connecting..."
 #构造HTTP头
 header = {'Referer':'http://cet.99sushe.com/'}
 #第二个参数出现则使用post方式提交
 req = urllib2.Request(cet, '', header)
 try:
 data = urllib2.urlopen(req).read()
 except BaseException, e:
 print "Error retrieving data:", e
 return -1
 if not len(result):
 print "Error Occured. Maybe record not existed."
 return -1
 #解码字符串
 result = data.decode("gb2312").encode("utf8")
 res_tu = tuple(result.split(','))
 score_tu = ("听力", "阅读", "综合", "写作", "总分", "学校", "姓名")
 print "n***** CET %s 成绩清单 *****" % (band)
 print "-准考证号: %s" % (exam_id)
 for i in range(7):
 print "-%s: %s" % (score_tu, res_tu)
 print "**************************n"
 print "准考证号前一位同学： %sn后两位同学分别是: %s、%s" % (res_tu[-3], res_tu[-2], res_tu[-1])
 return 0
if __name__ == "__main__":
 if (len(sys.argv) != 3) or
 (sys.argv[1] != '4' and sys.argv[1] != '6') or
 (len(sys.argv[2]) != 15):
 print "Error: 程序参数错误，考试类型（4、6），准考证号长度（15位）"
 print "nExample:nnCETQuery.py 4 123456789012345nn"
 print CetQuery.__doc__
 sys.exit(1)
 statue = CetQuery(sys.argv[1], sys.argv[2])
 sys.exit(statue)</div>

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　CET查分　

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