从任意进制的数转换成另外一个指定进制代码,C代码库,德仔网

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【C】从任意进制的数转换成另外一个指定进制

作者: / 发布于2014/5/22/ 542

从任意进制的数转换成另外一个指定进制


	#include <iostream>
	#include <string>

	std::string conv(std::string number, int startBase, int endbase);
	long long power(int num, int pow);

	int main(void){
	 std::string binary = "11010010";
	 std::cout << "Start Base: Binary (" << binary << ")" << std::endl;
	 std::cout << "Octal:\t\t" << conv(binary, 2, 8) << std::endl;
	 std::cout << "Decimal:\t" << conv(binary, 2, 10) << std::endl;
	 std::cout << "Hexadecimal:\t" << conv(binary, 2, 16) << std::endl << std::endl;

	 std::string octal = "81";
	 std::cout << "Start Base: Octal (" << octal << ")" << std::endl;
	 std::cout << "Binary:\t\t" << conv(octal, 8, 2) << std::endl;
	 std::cout << "Decimal:\t" << conv(octal, 8, 10) << std::endl;
	 std::cout << "Hexadecimal:\t" << conv(octal, 8, 16) << std::endl << std::endl;

	 std::string decimal = "41";
	 std::cout << "Start Base: Decimal (" << decimal << ")" << std::endl;
	 std::cout << "Binary:\t\t" << conv(decimal, 10, 2) << std::endl;
	 std::cout << "Octal:\t\t" << conv(decimal, 10, 8) << std::endl;
	 std::cout << "Hexadecimal:\t" << conv(decimal, 10, 16) << std::endl << std::endl;

	 std::string hexadecimal = "A9";
	 std::cout << "Start Base: Hexadecimal (" << hexadecimal << ")" << std::endl;
	 std::cout << "Binary:\t\t" << conv(hexadecimal, 16, 2) << std::endl;
	 std::cout << "Octal:\t\t" << conv(hexadecimal, 16, 8) << std::endl;
	 std::cout << "Decimal:\t" << conv(hexadecimal, 16, 10) << std::endl << std::endl;
	 return 0;
	}

	std::string conv(std::string number, int startBase, int endBase){
	 if(startBase > 16 || endBase > 16) return "BASE ERROR";
	 char NUMS[] = "0123456789ABCDEF";
	 std::string result = "";
	 int temp = 0, x;
	 bool found = false;
	 for(int i = 0; i < number.length(); i++){
	 for(x = 0; x < startBase; x++){
	 if(NUMS[x] == number[number.length()-(i+1)]){
	 found = true;
	 break;
	 }
	 }
	 if(!found) return "NUMBER ERROR";
	 temp += (x*power(startBase, i));
	 }
	 do{
	 result.push_back(NUMS[temp%endBase]);
	 temp /= endBase;
	 }while(temp != 0);
	 return std::string(result.rbegin(), result.rend());
	}

	long long power(int num, int pow){
	 if(pow == 0) return 1;
	 return num*power(num, pow-1);
	}

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